" (5) "5m^(2)+2m+1=0

Solve the following quadratic equations : 5m^(2)+2m+1=0

Solve the following quadratic equations : 5m^(2)+2m+1=0

If m+ (1)/(m-2)=0 , find m^(5) + m^(4) + m^(3) + m^(2)+ m+1 = ?

Simplify (2. 5 m + 1. 5q) ^(2) + (2. 5m - 1. 5q) ^(2)

If m+ (1)/(m+2)= 0 find m^(4) + m^(3) + m^(2) + m+1 =?

One of the roots of equation 5m^(2)+2m+k=0 is -7/5 . Find the value of 'k'.

One of the roots of equation 5m^(2)+2m+k=0 is -7/5 . find the value of 'k'.

Let m be a positive integer and Delta_(r)=|(2r-1,""^(m)C_(r),1),(m^(2)-1,2^(m),m+1),(sin^(2)(m^(2)),sin^(2)(m),sin^(2)(m+1))|(0lerlem) Then the value of sum_(r=0)^(m)Delta_(r ) is given by a)0 b) m^(2)-1 c) 2^(m) d) 2^(m)sin^(2)(2^(m))

If 3m -(1)/(3m) = 3, m ne 0 , then m^(2) + (1)/(81 m^(2)) is equal to