What is the amplitude of the function
`f(x) = 1/2 cos(3x + pi)`?

The range of the function f(x)=1/(2-"cos" 3x) is

Find the period of the function f(x) = sin((pi x)/3) + cos ((pi x)/2) .

Find the period of the function f(x) = sin((pi x)/3) + cos ((pi x)/2) .

Extend the defination of the function f(x) = (1-cos[7(x-pi)])/(5(x-pi)^2), x ne pi by continuity at x = pi

The range of the function f(x) = log_(sqrt5)(3 + cos ((3pi)/4 + x) + cos ((pi)/4 + x) + cos ((pi)/4 - x) - cos ((3pi)/4 - x)) is :

The range of the function f(x) = log_(sqrt5)(3 + cos ((3pi)/4 + x) + cos ((pi)/4 + x) + cos ((pi)/4 - x) - cos ((3pi)/4 - x)) is :

The period of the function f(x)=k cos kx is (pi)/(2) . The amplitude of f is

Discuss the continuity of the function f(x) ={:{((1+cos x)/(tan^2 x) ", "x ne pi),((1)/(2) ", " x=pi):}, at x=pi .

Discuss the continuity of the function f(x) ={:{((1+cos x)/(tan^2 x) ", "x ne pi),((1)/(2) ", " x=pi):}, at =pi .

I : The range of the function f(x)=cos[x]" for "-pi//2 lt x lt pi//2 is {1, cos 1, cos 2} . II. Every periodic function is one one.