An artificial satellite revolves around the earth in circular orbit of radius `r` with time period `T`. The satellite is made to stop in the orbit which makes it fall onto the earth. Time of fall of the satellite onto the earth is given by

An artificial satellite is revolving around the earth in a circular orbit of radius r. If the time period of revolution of the satellite is T, show that T^2 prop r^3 .

A satellite is orbiting around the earth with orbital radius R and time period T. The quantity which remains constant is

An artificial satellite revolves around the earth in a circular orbit and is at a height of 300 km above the surface of the earth. Find the orbital speed and the time period of the satellite. The radius of the earth=6400 km, g=980 cm*s^(-2) .

A satellite is revolving round the earth in an orbit of radius r with time period T. If the satellite is revolving round the earth in an orbit of radius r + Deltar(Deltar lt lt r) with time period T + DeltaT(DeltaT lt lt T) then.

A satellite is revolving round the earth in an orbit of radius r with time period T. If the satellite is revolving round the earth in an orbit of radius r + Deltar(Deltar lt lt r) with time period T + DeltaT(DeltaT lt lt T) then.

A satellite is revolving around the earth in a circular orbit at an altitude h where the acceleration due to gravity is g'. If the earth is a sphere of radius R then the period of the satellite is give by