The value of y in -5x+10y=100 at x=0 is………

Find the value of (x+y),if 5x-2y=10,x+8y=26

Find the value of x:y, if (8x-10y)/(3x+4y) = (4)/(5) .

Write the solution of the equation 5x-10y+5=0 and x-2y+1=0 .

Find the values of x and y if X = Y, where X = [(x + 10, y^2 + 2y),(0, -4)] and Y = [(3x+4, 3),(0, y^2 - 5y)] .

Distance between the lines 5x+12y-1=0 and 10x+24y+k=0 is 2, then the value of k is :

The minimum value of Z = 5x - 4y subject to constraints x+y le 10 , y le 4, x,y gt 0 will be at the point