`int(dx)/(sqrt(2x-x^2) = a^n sin^-1[x/a-1]`
The vale of n is
You may use dimensional analysis to solve the problem.

int(dx)/(sqrt(2x-x^2) = a^n sin^-1[x/a-1] The value of n is You may use dimensional analysis to solve the problem.

int(dx)/(sqrt(1-x^(2))(sin^(-1)x)^(2))

Given that int (dx)/(sqrt(2 ax - x^2)) = a^n sin^(-1) ((x-a)/(a)) where a is a constant. Using dimensional analysis. The value of n is

Given that int (dx)/(sqrt(2 ax - x^2)) = a^n sin^(-1) ((x-a)/(a)) where a is a constant. Using dimensional analysis. The value of n is

int(dx)/(sqrt(2)ax-x^(2))=a^(n)sin^(-1){(x-a)/(a)}a->