Sum of n terms of series `12+16+24+40+....` (A) `2(2^n -1)+8n` (B) `2(2^n-1)+6n` (C) `3(2^n-1)+8n` (D) `4(2^n-1)+8n`

The arithmetic mean of the series 1,2,4,8,16,....2^(n) is (2^(n)-1)/(n+1) (b) (2^(n)+1)/(n) (c) (2^(n)-1)/(n) (d) (2^(n+1)-1)/(n+1)

The sum of n terms of a series is An^(2)+Bn then the n^(th) term is (A) A(2n-1)-B(B)A(1-2n)+B(C)A(1-2n)-B(D)A(2n-1)+B

Find the sum of n terms of the series (1)/(2*4)+(1)/(4*6)+... (A) (n)/(n+1) (B) (n)/(4(n+1)) (C) (1)/((2n)(2n+2))( D) )(1)/(2^(n)(2^(n)+2))

Sum of the first n terms of the series 1/2+3/4+7/8+(15)/(16)+......... is equals to (a). 2^n+n-1 (b). n-1+2^(-n) (c). n+2^(-n)-1 (d). 2^n+1

Sum of the first n terms of the series 1/2+3/4+7/8+(15)/(16)+......... is equals to (a). 2^n-n-1 (b). 1-2^(-n) (c). n+2^(-n)-1 (d). 2^n+1

Sum of the first n terms of the series 1/2+3/4+7/8+(15)/(16)+......... is equals to (a). 2^n-n-1 (b). 1-2^(-n) (c). n+2^(-n)-1 (d). 2^n+1

Sum of series : 1+2+3+......... +n is (A) ((n)(n+1))/2 (B) n(n+1) (C) ((n+1)(n+2))/2 (D) none of these.

Sum of the first n terms of the series 1/2+3/4+7/8+(15)/(16)+......... is equals to (a). 2^n-n-1 (b). 1-2^(-n) (c). n+2^(-n)-1 (d).None of these

The sum to infinity of the series 1+2(1-(1)/(n))+3(1-(1)/(n))^(2)+ . . .. . . . , is (A) n^(2) (B) n(n+1) (C) n(1+(1)/(n))^(2) (D)None of these

The sum to infinity of the series 1+2(1-(1)/(n))+3(1-(1)/(n))^(2)+ . . .. . . . , is (A) n^(2) (B) n(n+1) (C) n(1+(1)/(n))^(2) (D)None of these