The resistance of a circular coil of 50 turns and 10 cm diameter is `5Omega`. What must be the potential difference across the ends of the coil so as to nullify the earth's magnetic field (H=0.314 gauss) at the centre of the coil? How should the coil be placed to achieve this result?

A coil of 50 turns and 10cm diameter is made out of a wire of resistivity 2 xx 10^(-6) Omega cm and cross sectional radius 0.1mm. The coil is connected to a source of EMF 10 V and of negligible internal resistance. (a) Find the current through the coil (b) What must be potential difference across the coil so as to nullify the horizontal component of earth's magnetic field, 0.314 xx 10^(-4) T at the centre of the coil. How should the coil be placed to achieve. this result?

A coil of 50 turns and 20 cm diameter is made with a wire of 0.2 mm diameter and resistivity 2xx10^(-6)Omega cm .The coil is connected to a source of EMF . 20 V and negligible internal resistance. (a)Find the current through the coil. (b)What must be the minimum potential difference across the coil so as to nullify the earth's horizontal magnetic induction 3.14xx10^(-5) tesla at the centre of the coil.How should the coil be placed to achieve the above result.

A circular coil of 50 turns and radius 0.2 cm carries a current of 12 A. Find magnetic field at the centre of the coil.

A circular coil of 100 turns has a radius of 10 cm and carries a current of 5A. Calculate the magnetic field (a) at the centre of the coil (b) at a point on the axis of the coil at a distanceof 5cm from the centre of the coil.

A circular coil of 300 turns and diameter 14 cm carries a current of 15 A. what is the magnitude of magnetic moment associated with the coil?

A circular coil of radius 10 cm having 100 turns carries a current of 3.2 A. The magnetic field at the center of the coil is