A points `P` moves such that its distances from `(1,2)` and `(-2,3)` are equal. Then, the locus of `P` is

If a point P moves such that its distance from the point A(1,1) and the line x+y+2 are equal then the locus is

A point P moves such that its distances from two given points A and B are equal. Then what is the locus of the point P ?

A point P(x,y) moves so that the sum of its distances from point (4,2) and (-2,2) is 8. If the locus of P is an ellipse then its length of semi-major axis is

ABCD is a square with side AB=2. A point P moves such that its distance from A equals its distance from the line BD.The locus of P meets the line AC at T_(1) and the line through A parallel to BD at T_(2) and T_(3). The area of the triangle T_(1)T_(2)T_(3) is :

ABCD is a square with side AB = 2. A point P moves such that its distance from A equals its distance from the line BD. The locus of P meets the line AC at T_1 and the line through A parallel to BD at T_2 and T_3 . The area of the triangle T_1 T_2 T_3 is :

ABCD is a square with side AB = 2. A point P moves such that its distance from A equals its distance from the line BD. The locus of P meets the line AC at T_1 and the line through A parallel to BD at T_2 and T_3 . The area of the triangle T_1 T_2 T_3 is :

If a point P moves such that its distance from the point A(1, 1 ) and the line x + y + 2 = 0 are equal then the locus of P is