An ice skater starts a spin with her arms stretched out to the sides. She balances on the tip of one skate to turn without friction. She then pulls her arms in so that her moment of inertia decrease by a factor of `2`. In the process of her doing so, what happens to her kinetic energy ?

A gymnast takes turns with her arms and legs stretched. When she pulls her arms and legs in

An ice skater spins with arms outstretched at 1.9 rps. Her moment of inertia at this instant is 1.33 kg m^2 . She pulls in her arms to increase her rate of spin. If the moment of inertia is 0.48 kg m^2 after she pulls in her arms, what is her new rate of rotation ?

An ice skater has her arms outstretched and is spinning with a rate of 2 rotations per second. Her moment of inertia at this instant is 1.48kgm^(2) . She then pulls her arms inside to increase her rate of spin and her moment of inertia becomes 0.56kgm^(2) . Calculate her new rate of rotation.

A battet dancer spins with 2.8 rps with her arms out stretched. When the moment of inertia about the same axis becomes 0.7 l. the new rate of spin is

A dancer on ice spins faster when she folds her arms due to

A dancer on ice spins faster when she folds her arms due to

A dancer is standing on a stool rotating about the vertical axis passing through its centre. She pulls her arms towards the body reducing her moment of inertia by a factor of n. The new angular speed of turn table is proportional to