If `xdy=ydx+y^2dy` and `y(1)=1`, then `y(-3)` is equal to (A) `1` (B) `5` (C) `4` (D) `3`

If xdy=y(dx+y dy), y gt 0 and y(1)=1 , then y(-3)=

If xdy =y(dx+ydy),y(1)=1andy(x)gt0 , then y(-3) is equal to a)3 b)2 c)1 d)0

If xdy=y(dx+ydy);y(1)=1 and y(x)>0 then what is y(-3) equal to?

If x dy =y (dx+y dy), y(1) =1 and Y(x)gt 0 . Then, y (-3) is epual to (a) 3 (b) 2 (c) 1 (d) 0

If x^(3)dy+xydx=x^(2)dy+2ydx,y(2)=e then y(-1)=

If x^(3)dy+xydx=x^(2)dy+2ydx,y(2)=e then y(-1)=

For the primitive integral equation y dx+y^2dy=xdy ; x in R ,y >0,y(1)=1, then y(-3) is (a) 3 (b) 2 (c) 1 (d) 5

For the primitive integral equation y dx+y^2dy=xdy ; x in R ,y >0,y(1)=1, then y(-3) is (a) 3 (b) 2 (c) 1 (d) 5