I = `int_0^(pi/2) (2 cos x + 3)/(cos x + 3)^2 dx`

int_0^(pi//2) x^2 cos 2x dx

int_0^(pi//2) (cos x)/(3 cos x+sin x) dx

int_(0)^(pi) dx/(3+2sin x + cos x) =

int_0^pi (cos^2x)dx ,

Evaluate the following integrals (i) int_(0)^(pi/2)(2 sin x + 3 cos x)/(sin x + cos x)dx

int_(0)^( pi)sin^(3)x(1+2cos x)(1+cos x)^(2)dx

int_ (0) ^ ((pi) / (2)) (sin x) / (sin x + cos x) dx = int_ (0) ^ ((pi) / (2)) (cos x) / (sin x + cos x) dx = int_ (0) ^ ((pi) / (2)) (dx) / (1 + cot x) = int_ (0) ^ ((pi) / (2)) (dx) / ( 1 + time x) = (pi) / (4)

Evaluate int_0^(pi//2) (dx)/(3+cos^2x)

I=int_(0)^(2 pi)cos^(-1)(cos x)dx

int_(0)^(pi//2)(sin x cos x dx)/(cos^(2)x+3cosx+2)=