In following figure if AD if the bisector of `angleABC,` then prove that `AB gt BD`

In the figure,AD is the bisector of angle BAC. Prove that AB>BD.

In DeltaABC , if AD is the bisector of angleA , show that AB gt BD and AC gt DC .

In Figure,if AD is the bisector of LA, show that: AB>BD( ii) AC>CD

In the given figure of AD = CB then prove that AC = BD

In the adjoining figure, bisector of angleBAC intersects BC at point D. Prove that AB gt BD .

In the adjoining figure, DeltaABC is an isosceles triangle in which AB = AC and AD is the bisector of angleA . Prove that: BD = CD

In triangleABC , if the AD is a bisector of angleA show that AB>BD and AC>CD

In the given figure, if AC = BD, then prove that AB = CD.

In the given figure, if AC = BD, then prove that AB = CD.