The radical centre of the circles `x^(2) + y^(2) = 1, x^(2) + y^(2) - 2x - 3 = 0` and `x^(2) + y^(2) - 2y - 3 = 0` is

The radical centre of the circles x^(2) + y^(2) +1=0 , x^(2) + y^(2) - 2x - 3 = 0 " and " x^(2) + y^(2) - 2y - 3 = 0 is

The radical centre of the circles x^(2) + y^(2) = 1 , x^(2) + y^(2) - 2x = 1 , x^(2) + y^(2) - 2y = 1 is

The radical centre of the circles x^(2) + y^(2)- 2x + 6y = 0 , x^(2) + y^(2) - 4x - 2y + 6 = 0 , x^(2) + y^(2) - 12x + 12y + 30 = 0 is

The radical centre of the circles x^(2) + y^(2) - x + 3y-3 = 0 , x^(2) + y^(2) - 2x + 2y + 2= 0 , x^(2) + y^(2) + 2x +3y - 9 = 0 is

Coordinates of the centre of the circle which bisects the circumferences of the circles x^2 + y^2 = 1; x^2 + y^2 + 2x - 3 = 0 and x^2 + y^2 + 2y-3 = 0 is

Find the radical centre of the circles x^(2)+y^(2)+4x=7=0, 2x^(2)+2y^(2)+3x+5y-9=0 and x^(2)+y^(2)+y=0.

Coordinates of the centre of the circle which bisects the circumferences of the circles x^(2)+y^(2)=1;x^(2)+y^(2)+2x-3=0 and x^(2)+y^(2)+2y-3=0 is

The radical centre of three circles : x^2 + y^2 + x + 2y + 3 = 0, x^2 + y^2 + 2x + 4y + 5 = 0 and x^2 + y^2 - 7x - 8y - 9 = 0 is : (A) (- 2/3, - 2/3) (B) (1/3, 1/3) (C) (1/4, 1/4) (D) (0, 0)