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In an isosceles right angled triangle , ...

In an isosceles right angled triangle , a straight line drwan from the mid - point of one of equal sides to the opposite angle . It divides the angle into two parts , `theta and (pi//4-theta)` . Then `tan theta and tan [(pi//4) -theta]` are equal to

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tan(pi/4 + theta) tan (pi/4 -theta)=

tan(pi/4 + theta) + tan(pi/4-theta)=4

tan(pi/4+theta)+tan(pi/4-theta)=4

tan(pi/4+theta/2)+tan(pi/4-theta/2) is equal to

tan(pi/4+theta)-tan(pi/4-theta)=

Show that tan (pi/4+theta/2)=sec theta +tan theta .

tan(pi/4+theta)-tan(pi/4-theta)=2tan2theta

tan ((pi)/(4)+theta) tan ((3pi)/( 4) + theta) is equal to

If tan (pi//4 + theta) + tan (pi//4 - theta) = 4 , then theta =

tan(pi/4+theta)tan((3pi)/4+theta) is equal to