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If I(n)=int(sinx+cosx)^(n)dx, snd I(n)=1...

If `I_(n)=int(sinx+cosx)^(n)`dx, snd `I_(n)=1/n(sinx+cosx)^(n-1)(sinx-cosx)+(2k)/(n) I_(n-2)` then k=

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