A marble statue of height `h_1` metres is mounted on a pedestal. The angles of elevation of the top and bottom of the statue from a point `h_2` metres above the ground level are `alpha and beta` respectively. Show that the height of the pedestal is `((h_1 - h_2)tan beta + h_2 tan alpha)/(tan alpha - tan beta).`

From the top and bottom of a building of height h metres, the angles of elevation of the top of a tower are alpha and beta respectively. Then the height of the tower is :

A window of a house is h metres above the ground. From the window, the angles of elevation and depression of the top and bottom of another house situated on the opposite side of the lane are found to be alpha and beta respectively. Prove that the height of the house is h(1 + tan alpha cdot tan beta) metres.

From a window h m high above the ground in a street, the angles of elevation and depression of the top and foot of the other house on the opposite side of the street as alpha and beta respectively show that height of the opposite house is h(1+tan alpha cos beta)m .

If the angles of depression of the upper and lower ends of a lamp post from the top of a hill of height h metres are alpha and beta respectively, the height of the lamp post (in metres) is

If the angle of elevation of a cloud from a point h metres above the surface of a lake is alpha and the angle of depression of its reflexion in the lake is beta , prove that the height of the cloud is (h (tan beta + tan alpha))/(tan beta - tan alpha) metres.

If the angle of elevation of a cloud from a point h metre above the lake is alpha and the angle of depression of its reflection in the lake is beta , prove that the height of the cloud above the lake is (h(tan beta+tan alpha))/(tan beta- tan alpha)

A window of a house is h metres above the ground. From the window, the angles of elevation and depression of the top and the bottom of another house situated on the opposite sides of the lane are found to be alpha and beta respectively. Prove that the height of the other house is h(1 + tan alpha cot beta) metres.

A bridge across a valley is h metres long. There is a temple in the valley directly below the bridge. The angles of depression of the top of the temple from the two ends of the bridge are alpha and beta . Prove that the height of the bridge above the top of the temple is (h (tan alpha tan beta))/(tan alpha + tan beta) metres.

If the angle of elevation of a cloud from a point h metres above a lake is alpha and the angle of depression of its reflection in the take is beta prove that the height of the cloud is h(tan beta+tan alpha)quad tan beta-tan alpha