An electron accelerated by a potnetial difference `V = 1.0 kV` moves in a unifrom magentic field at angle `alpha = 30^(@)` to the vector `B` whose modulus is `B = 29 mT`. Find the pithch of the helical trajectroy of the electron.

An electron accelerated by a potential difference V=1.0 kV moves in a uniform magnetic field at an angle alpha = 30^@ to the vector B whose modulus is B=29 mT. Find the pitch of the helical trajectory of the electron.

An electron accelerated by a potential difference V=1.0 kV moves in a uniform magnetic field at an angle alpha = 30^@ to the vector B whose modulus is B=29 mT. Find the pitch of the helical trajectory of the electron.

An electron accelerated by a potential difference V= 3 volt first enters into a uniform electric field of a parallel plate capacitor whose plates extend over a length l= 6 cm in the direction of initial velocity. The electric field is normal to the direction of initial velocity and its strength varies with time as E= alpha t, where alpha= 3600 V m^-1 s^-1. Then the electron enters into a uniform magnetic field of induction B = pi xx 10^-9 T. Direction of magnetic field is same as that of the electric field. Calculate pitch of helical path traced by the electron in the magnetic field. (Mass of electron, m = 9 xx 10^-31 kg )

An electron accelerated by a potential difference V= 3 volt first enters into a uniform electric field of a parallel plate capacitor whose plates extend over a length l= 6 cm in the direction of initial velocity. The electric field is normal to the direction of initial velocity and its strength varies with time as E= alpha t, where alpha= 3600 V m^-1 s^-1. Then the electron enters into a uniform magnetic field of induction B = pi xx 10^-9 T. Direction of magnetic field is same as that of the electric field. Calculate pitch of helical path traced by the electron in the magnetic field. (Mass of electron, m = 9 xx 10^-31 kg )

An electron of mass m and charge e is accelerated by a potential difference V. It then enters a uniform magnetic field B applied perpendicular to its path. The radius of the circular path of the electron is

An electron of mass m and charge e is accelerated by a potential difference V. It then enters a uniform magnetic field B applied perpendicular to its path. The radius of the circular path of the electron is

An electron accelerated in an electric field of 20 kV enters a uniform magnetic field with induction 0.1 T. Its velocity vector makes an angle of 75^@ with the magnetic field vector. Find the shape of the path.

A proton accelarted by a potential differnce V = 500 kV fieles through a unifrom transverse magnetic filed the induction B = 0.54 T . The field occupies a region of space d = 10 cm in thickness (Fig). Find the angle alpha through which the proton deviates from the initial direction of its motion.