5, 1001. Total number of different values of Consider the equation x +2x n' so that the given equation has integral roots, is (A) 4 -n O, where n c N and n

Consider the equation x^2+2x-n=0 where n in N and n in [5,100] The total number of different values of n so that the given equation has integral roots is a. 8 b. 3 c. 6 d. 4

Consider the equation x^2+2x-n=0 where n in N and n in [5,100] The total number of different values of n so that the given equation has integral roots is a. 8 b. 3 c. 6 d. 4

Consider the equation x^2+2x-n=0 where n in N and n in [5,100] The total number of different values of n so that the given equation has integral roots is a. 8 b. 3 c. 6 d. 4

Consider the equation x^(2) + 2x - n = 0 m where n in N and n in [5, 100] . The total number of different values of n so that the given equation has integral roots is

Consider the equation x^(2)+2x-n=0 where n in N and n in[5,100] The total number of different values of n so that the given equation has integral roots is a.8 b.3 c. 6d.4

consider the equation x^(2)+x-n=0 where a is an integer lying between 1 to 100. Total number of different values of n so that the equation has integral roots,is

Total number of integral values of 'n' so that sinx(sinx+cosx) = n has at least one solution , is :

The number of integral values of n such that the equation 2n{x}=3x+2[x]has exactly 5 solutions.

The number of integral values of 'n' so that sin x (sin x + cos x ) =n has at least one solution