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The length of projection of i+2j+3k in t...

The length of projection of i+2j+3k in the direction of 3i-4j+5k is

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{:(I."Area of the parallelogram with diagonals" 3i + j - 2k. i - 3j + 4k, a.(sqrt(569))/(4)), (II. "Area of the triangle whose adjacent sides are" 3i + 4j "and" i - 3j + 4k, b. (2)/(sqrt(14))),(III. "Volume of parallelopiped whose edges are" 2i - 3j. i + j - k. 3i - k, c. 5 sqrt(3)),(IV. "Projection of" 2i + 3j - 2k "in the direction of" i + 2j + 3k, d. 4),(, e. 2//3)):}"

A : Length of projection of 2i - 3j + k along 4i - 4j + 7k is 3 R : Length of projection of b on a is (a.b)/(|b|)

The projection of a = 3i - j + 5k on b = 2i + 3j +k is

The direction cosines of the vector, 3i-4j+5k are

The projection of veca=2i+3j -2k on vecb=i+2j+3k is

If veca=3i+j+2k, If the projection of veca on another vector vecb is sqrt14 , which among the following could be vecb ? i+j+k 6i+2j+4k 3i-j+2k 2i+3j+k