A stone of mass 2 kg is projected upwards with KE of 98 J. The height at which the KE of the body becomes half its original value, is given by (take, `g=9.8ms^(-2)`)

A body of mass 5 kg is thrown vertically up with a kinetic energy of 490 J.The height at which the kinetic energy of the body becomes half of the origibnal value is

A body of mass 1 kg is thrown vertically upwards with initial K.E. of 98 joule. The height at which its energy is reduced to half will be

A body of mass 5 kg is thrown vertically up with a kinetic energy of 490 J. What will be height at which the kinetic energy of the body becomes half of the original value ? (Acceleration due to gravity =9.8ms^(-2) )

A body of mass 5 kg is thrown vertically up with a kinetic energy of 490 J. What will be height at which the kinetic energy of the body becomes half of the original value ? (Acceleration due to gravity =9.8ms^(-2) )

A body of mass 2 kg is projected vertically upward with a velocity of 2msec^(-1) . The K.E. of the body just before striking the ground is

A ball is throuwn vertially up with a velcity of 20ms^(-1) . At height , will its K.E. be half its orginal value?

A body of mass 2 kg is thrown vertically upwards with K.E of 245 J. The acceleration due to gravity is 9.8 ms^(-2) . The K.E. Of the body will become half at the height of