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(vi)=((x^(2)+1)/(x^(2)))^(3)...

(vi)=((x^(2)+1)/(x^(2)))^(3)

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" (vi) "int((x^(2)+1)/(x^(2)))dx

Expand using binomial theorem: (i) (1-2x)^(4) " " (ii) (x+2y)^(5) (iii) (x-(1)/(x))^(6) " "(iv) ((2x)/(3)=(3)/(2x))^(5) (v) (x^(2) +(2)/(x))^(6)" "(vi) (1+(1)/(x^(2)))^(4)

(i) (3x^(2) +4x-5)/x (ii) ((x^(3) +1)(x-2))/x^(2) (iii) (x-4)/(2sqrtx) (iv) (( 1+x)sqrtx)/root3(x) (v) (ax^(2) +bx+c)/sqrtx (vi) (a+b cos x)/sin x

Find the term independent of x (constant term) in the following expansion: (i) (x^(2)-(1)/(3x))^(9) " "(ii) (x-(1)/(x))^(10) (iii) (3x-(2)/(x^(2)))^(18) " "(iv) (1)/(x^(n))(1+x)^(2n) (V)(3sqrt(x)+(1)/(2(3sqrt(x))))^(18)" "(vi)((3x^(2))/(2)-(1)/(3x))^(6)

Resolve into Partial Fractions (vi) (5x^(2)+2)/(x^(3)+x)

Resolve into Partial Fractions (vi) (5x^(2)+2)/(x^(3)+x)

Check whether the following equations are quadratic or not . (i) x^(2) - 6x - 4 = 0 (ii) x^(3) - 6x^(2) + 2 x - 1 = 0 (iii) 7x = 2x^(2) (iv) x^(2) + (1)/(x^(2)) = 2 (v) (2x + 1 ) (3 x + 1 ) = 6 (x - 1) (x - 2) (vi) 3y^(2) = 192

Which of the following are quadratic equations? (i) x^(2)-5x+3=0 (ii) 2x^(2)-3sqrt(2)x+6=0 (iii) 3x^(2)-2sqrtx+8=0 (iv) 2x^(2)-3=0 (v) x+(1)/(x)=x^(2) (vi) x^(2)+(1)/(x^(2))=4(1)/(4)