int(1)/(9x^(2)+6x+5)dx

int (1)/(9x^(2)+16)dx=

int(1)/(9x^(2)+4)dx

Evaluate: (i) int(1)/(4+9x^(2))dx (ii) int(1)/(9x^(2)-4)dx (iiii) int(1)/(16-9x^(2))dx

Evaluate: int1/(x^2+6x+5)dx

int 1/(9x^2-1) dx

int(dx)/(9x^(2) +1)

int(dx)/(9x^(2)+6x+10)

If int(x+2)/(2x^(2)+6x+5)dx =P int(4x+6)/(2x^(2)+6x+5)dx+(1)/(2) int (dx)/(2x^(2)+6x+5') Then the value of P is

int(1)/(6+5x-6x^(2))dx