Balmer series of hydrogen atom lies in

The wavelength of the first Balmer line Li^(2+) ion is 136800 cm^(-1) .The wavelength of the first line of Balmer series of hydrogen atom is ("in" cm^(-1))

The wave number of the first Balmer line Li^(2+) ion is 136800 cm^(-1) .The wave number of the first line of Balmer series of hydrogen atom is ("in" cm^(-1))

The wave number of limiting line in Balmer series of hydrogen atoms is

Which is the shortest wavelength in the Balmer series of hydrogen atoms ?

If the wave number of the first line in the Balmer series of hydrogen atom is 1500cm^(-1) , the wave number of the first line of the Balmer series of Li^(2+) is

In Balmer series of hydrogen atom write - (i) the formula for calculating wavelength (ii) range of largest and smallest wavelength (iii) the region of the spectrum where this series lies .