A resistor `20Omega`, inductive reactance `15Omega` and capacitive reactance `15Omega` are connected in series to an AC voltage source `V=200sqrt(2)sin omega t`. Then the maximum current in the circuit is

A resistor 30 Omega , inductor of reactance 10 Omega and capacitor of reactance 10 Omega are connected in series to voltage source E = 300sqrt2 sin(omegat) . Find the current in the circuit.

A circuit has a resistance of 11 Omega , an inductive reactance of 25 Omega , and a capacitive resistance of 18 Omega . It is connected to an AC source of 260 V and 50 Hz . The current through the circuit (in amperes) is

A circuit has a resistance of 11 Omega , an inductive reactance of 25 Omega , and a capacitive resistance of 18 Omega . It is connected to an AC source of 260 V and 50 Hz . The current through the circuit (in amperes) is

A resistance of 400Omega and a capacitance of reactance 200Omega are connected in series to a 220V, 50Hz a.c source. If the current in the circuitsis 0-49A. Find voltage across resistor and capacitor

In an A.C. circuit, resistance = 12 Omega and capacitance reactance = 9 Omega are connected in series, then the value of impedance of a circuit will be ..........

In an experiment, 200V AC is applied at the end of an LCR circuit. The circuit consists of an inductive reactance (X_(L)) = 50Omega , capacitive reactance (X_(c)L=50Omega , and capacitives resistance (R ) = 10Omega , The impendance of the circuit is