" (vii) "(x+2)_(3)=2x(x-1)

Solve: (x+2)^3=2x(x^2-1)

Find the value of x in (x+2)(2x-3)=(2x+1)(x-2)

Check whether the following are quadratic equations : (1) (x-2)^(2)+1=2x-3 (2) x(x+1)=8=(x+2)(x-2) (3) x(2x+3)=x^(2)+1 (4) (x+2)^(3) = x^(3)-4

Factorise : (x^(2) -3x)(x^(2)-3x-1)-20

Determine the constant k, so that function f (x) is continuous at the indicated points : f(x)= {((x^2-3x+2)/(x-1),if,x,ne,1),(k,if,x,=,1):} at x=1.

Q.Determinethe value of the constant k so that the function f(x)={(x^(2)-3x+2)/(x-1), if x!=1,k, if x!=1 is continuous at x=1

Find the HCF and LCM of the following polynomials (x+2)^(2)(x-3)^(2)(x+1)^(2),(x+1)^(3)(x+2)^(3)(x-3)

3x^(2)+x(x+2)-3x(2x+1)

Simplify: (x^(3)-2x^(2)+3x-4)(x-1)-(2x-3)(x^(2)-x+1)

Simplify (x+2)(x^(2)-6x+8)-(2x-3)(2x^(2)-x-1)