ul(" SO ")quad I=int(0)^(1)ln((1)/(x)-1)...

ul(" SO ")quad I=int_(0)^(1)ln((1)/(x)-1)dx

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int_(0)^(1)log((1)/(x)-1)dx

int_(0)^(1)log((1)/(x)-1)dx=

I=int_(0)^(2)log((2)/(x)-1)dx

int_(0)^(1)log((1-x)/(x))dx=0

int_(0)^(1)(log(1-x))/(x)dx

int_(0)^(1) log (1/x-1) dx =

If I_(1)=int_(0)^(2pi)sin^(3)xdx and I_(2)=int_(0)^(1)ln((1)/(x)-1)dx , then

If I_(1)=int_(0)^(2pi)sin^(3)xdx and I_(2)=int_(0)^(1)ln((1)/(x)-1)dx , then

I=int_(-1)^(1)log((2-x)/(2+x))dx

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