" If the rate law for a reaction is rate "=k[A][B]^(2)" ,the units of "k" would be "

If the rate law of a reaction, is r=k[A][B]^(2) ,what would, be the new rate in, comparison to the original , one when the volume of , the vessel is reduced to , half of the original?

The rate law for a reaction is Rate = k[A]^(1//2)[B]^2 Can the reaction be an elementry reaction. Explain.

The rate law of a reaction is : Rate = k[A]^(2) [B] On doubling the concentration of both A and B the rate x will become :

The rate law for a certain reaction is found to be : Rate = k[A] [B]^(2) How will the rate of this reaction compare if the concentration of A is doubled and the concentration of B is halved ? The rate will :

If the rate of reaction between A and B is given by rate =k[A][B]^(2) , then the reaction is

If the rate of reaction between A and B is given by rate =k[A][B]^(2) , then the reaction is :