If a particle of charge q is moving with velocity v along the y-axis and the magnetic field B is acting along the z-axis, use the expression `vecF=q(vecvxxvecB)` to find the direction of the force `vecF` acting on it.

If a particle of charge q is moving with velocity v along x-axis and the magnetic field B is acting along Y-axis, use the expression vecF=q(vecv xx vecB) to find the direction of force vecF acting on it.

A particle with charge q is moving with a velocity vecv in a magnetic field vecB . If the force acting on the particle is vecF then,

If a particle of charge q is moving with a velocity v in a direction opposite to the magnetic field B, then the force acting on the particle is.

If a particle of charge q is moving with velocity vecv along y axis and a magnetic field vecb act along z axis, find the force acting on it. What happens to its kinetic energy ? Justify.

An electric charge q is moving with a velocity w in the direction of a magnetic field B. The magnetic force acting on the charge is

A charged particle of charge q moving with the velocity v, enters along the axis of a solenoid carrying a current. If B is the magnetic induction along the axis of the solenoid then the force acting on the charged particle will be

An electric charge q is moving with a velocity v in the direction parallel to the magnetic field B. The magnetic force acting on the charge is

The charge is moving along the direction of magnetic field. Then force acting on it is………

The force acting on a charge 'q' moving with a velocity V in a magnetic field of induction B is given by