A cell of emf E and internal resistance r is connected in series with an external resistance nr. Than what will be the ratio of the terminal potential difference to emf, if n=9.

A cell of e.mf. E and internal resistance r is connected in series with an external resistance nr. Then, the ratio of the terminal potential difference to E.M.F.is

A cell of e.mf. E and internal resistance r is connected in series with an external resistance nr. Then, the ratio of the terminal potential difference to E.M.F.is

A cell of e.m.f (E) and internal resistance (r) is connected in series with an external resistance (nr.) then the ratio of the terminal p.d. to E.M.F is

n cells of e.m.f E and internal resistance r are connected in series with an external resistance R . the current will increase n times that of a single cell, if

n identical cells, each of emf e and internal resistance r, are first connected in series and then in parallel. What will be the ratio of the emfs and of the internal resistances of these two cell combinations?