2y3-5y2-19y+42

The factors of 2y^3 - 5y^2 - 19y + 42 are :

Factorise : y^3 - 2y^2 - 29y - 42 .

y^(3)-2y^(2)-29y-42

3x^(2) + 8x +4=0, 4y^(2)-19y + 12=0

Show that the equation 2x^2-xy-3y^2-6x+19y-20=0 represents a pair of intersecting lines. Show further that the angle between them is tan^(-1) (5) .

Find the value of the polynomial: y^3-5y-2y^2+3 when y=2 and y=-2

Factories the following : 5x^(2)- 29xy - 42y^(2)

The polynomial 6y^4-19y^3-23y^2+10y+8 on factorization gives

Factorise: 7y^(2) - 19y -6