Six boys and six girls sit along a line alternately in x ways, and along a circle (again alternatively in ways), then

Six boys and six girls sit along a line alternately in x ways, and along a circle (again alternatively in y ways), then

Six boys and six girls sit along a line alternately in x ways , and along a circle again alternatively in y ways then

[" Six boys and six girls along a line "],[" alternately in "x" ways ";" and along a circle "],[" again alternately in "y" ways,then "],[[" (A) "x,=y],[" (B) "y,=12x],[" (C) "x,=10y],[" (D) "x,=12y]]

n boys and n girls sit alternately along a line inx ways and along a circle in y ways such that x = 10y , then the number of ways in which n boyscan sit around a round table so that none of themhas same two neighbours, is

Six boys and six girls sit in a row at random. The probability that the boys and girls sit alternatively is

n boys and n girls sit alternately along a line inx ways and along a circle in y ways such that x=10y, then the number of ways in which n boyscan sit around a round table so that none of themhas same two neighbours,is

Six boys and six girls sit in a row at random. Find the probability that : the boys and girls sit alternately.