solve for `x and y` if `x+y=(2pi)/3` and `(sinx)/(siny)=2`

solve for x and y if x+y=(2 pi)/(3) and (sin x)/(sin y)=2

If x+y=2pi//3 and sin x//siny=2 , then the

If x+y=2pi//3 and sin x//siny=2 , then the

Find the least positive values of x and y so that 2(sinx + siny)-2cos(x-y)=3 .

Solve: (dy)/(dx) = (siny+x)/(sin2y-xcosy)

If x+y=(2pi)/(3)andsinx+siny=(3)/(2)" then find"x ,y

Solve dy/dx+2ytanx=sinx , y=0 , x=pi/3

The total number of ordered pairs (x, y) satisfying |y|=cosx and y=sin^(-1)(sinx) , where x in [-2pi, 3pi] is equal to :

The total number of ordered pairs (x, y) satisfying |y|=cosx and y=sin^(-1)(sinx) , where x in [-2pi, 3pi] is equal to :

if x and y are acute angles such that cosx + cosy = 3/2 and sinx + siny = 3/4 then sin(x+y)=