if `y=a sin (log x) + b cos (log x )` , then the differential equation without the parameter a and b is

y = A cos (log x) + B sin (log x)

Form differential equation for y=A log x+B

The differential of log sin x is-

Differentiate log sin x with respect to x:

Solve the differential equation : x (dy/dx) + y = x log x

Solve the differential equations : x cos y dy = e^(x)(x log x+1)dx

Differentiate log(sin x) with respect to 'x'

Differentiate log(sin x) with respect to 'x'

Show that y =a cos (log x)+b sin (logx),x le 0 is a soluton of the differential equation x^(2)y''+xy'+y=0

If y =a cos (log x) + b sin (log x) then x ^(2) y _(2) + xy _(1)+y=