A car, starting from rest, accelerates at the rate f through a distance s, then continues at constant speed for time t and then decelerates at the rate f/ 2 to come to rest. If the total distance travelled is 15 s, then

A car, starting from rest, accelerates at the rate f through a distance S, then continues at constant speed for time t and then decelerates at the rate f/2 to come to rest. If the total distance traversed is 5 S, then :

A car,starting from rest, accelerates at the rate f through a distance s, then continuous at constant speed for time t and then decelerates at the rate f/2 come to rest. If the total distance traversed is 5 s,then :

A car , starting from rest, accelerates at the rate f through a distance S then continues at constant speed for time t and then decelerates at the rate (f)/(2) to come to rest . If the total distance traversed is 15 S , then

A car , starting from rest, accelerates at the rate f through a distance S then continues at constant speed for time t and then decelerates at the rate (f)/(2) to come to rest . If the total distance traversed is 15 S , then

A car starting from rest, accelerates at the rate of f through a distance S, then continues at constant speed for time t and declerates at the rate f/2 to come to rest. If the total distance travelled is 15 S then S =

A bus starting from rest, accelerates at the rate of f through a distance S, then continues at constant speed for time t and declerates at the rate f/2 to come to rest. If the total distance travelled is 15 S then S =

A car starting from rest,accelerates at the rate of f through a distance S,then continues at constant speed for time t and declerates at the rate f/2 to come to rest.if the total distance travelled is 15 S then S=

A car, starting from rest, accelerates at the rate (f) through a distance (S), then continues at constant speed for some time (t) and then decelerates at the rate f//2 to come to rest. If the total distance is 5 S , then prove that S=1/2/ ft^(2) .