Force constant of a spring is 100 `N//m`. If a 10kg block attached with the spring is at rest, then find extension in the spring.
`( g= 10 m//s^(2)`)

In spring constant of the spring is 100 N//m Extension produced in the spring is: (g=10 m//s^(2))

In the figure shown, all surfaces are smooth and force constant of spring is 10N//m . Block of mass (2 kg) is attaced with the spring. The spring is compressed by (2m) and then released. Find the maximum distance d travelled by the block over the inclined plane. Take g=10m//s^(2) . .

In the figure shown, all surfaces are smooth and force constant of spring is 10N//m . Block of mass (2 kg) is attaced with the spring. The spring is compressed by (2m) and then released. Find the maximum distance d travelled by the block over the inclined plane. Take g=10m//s^(2) . .

A block of mass 20 kg is hung with the help of ideal string, pulleys and spring (Spring constant k = 1000 N/m) as shown in figure. If block is in equilibrium position then extension in the spring will be (g = 10 ms^-2)

Natural length of a spring is 60 cm and its spring constant is 4000 N/m. A mass of 20 kg is hung from it. The extension produced in the spring is (Take, g = 9.8 m//s^(2) )

Natural length of a spring is 60 cm and its spring constant is 4000 N/m. A mass of 20 kg is hung from it. The extension produced in the spring is (Take, g = 9.8 m//s^(2) )

A block of mass 5 kg is released from rest when compression in spring is 2m . Block is not attached with spring and natural length of the spring in 4m . Maximum height of block from ground is :(g=10m//s^(2))

A block of mass 5 kg is released from rest when compression in spring is 2m . Block is not attached with spring and natural length of the spring in 4m . Maximum height of block from ground is :(g=10m//s^(2))

A spring executes SHM with mass off 10 kg attached to it. The force constant of spring is 10 N//m . If at any instant its velocity is 40cm/s , the displacement will be (where amplitude is 0.5m)