यदि पृथ्वी की त्रिज्या `6.4xx10^(6)m, ` पृथ्वी पर गुरुत्वीय त्वरण `9.8m//s^(2)` और गुरुत्वाकर्षण नियतांक ` 6.7xx10^(-11)Nm^(2)//kg^(2)` हो, तो पृथ्वी का द्रव्यमान निकले |

G = 6.67 xx 10^(-11) kg^(-1) m^(3) s^(-2) . Convert it into CGS system.

The mean radius of a planet is 6.67xx10^(3) km. The acceleration due to gravity on its surface is 10 m//s^(2) . If G = 6.67xx10^(-11)Nm^(2)//kg^(2) , then the mass of the planet will be [R=6.67xx10^(6)m]

The mean radius of a planet is 6.67xx10^(3) km. The acceleration due to gravity on its surface is 10 m//s^(2) . If G = 6.67xx10^(-11)Nm^(2)//kg^(2) , then the mass of the planet will be [R=6.67xx10^(6)m]

Find the escape velocity of a body from the earth. [R(earth) =6.4xx10^(6)m, rho" (earth)"=5.52xx10^(3)kg//m^(3), G=6.67xx10^(-11)N.m^(2)//kg^(2)]

Calculate mass of earth taking it to ne a sphere of radius 6400 km. given g=9.8 m//s^(2) and G=6.67xx10^(-11)N m^(2)kg^(-2)

Find the escape velocity of a body from the earth. [M (earth ) = 6 xx 10^(24) kg, R ( earth) = 6.4 xx 10^(6) m. G = 6.67 xx 10^(-11) N.m^(2)//kg^(2)]

The radius of the moom is 1.7 xx 10^(6) m and its mass is 7.4 xx 10^(22) kg . If G = 6.67 xx 10^(-11) Nm^(2) kg^(-2) , find the value of acceleration due to gravity on the surface of moon.

The radius of the earth is 6.37 xx 10^(6) m and its mean density is 5.5 xx 10^(3) "kg m"^(-3) and G = 6.67 xx 10^(-11) "N-m"^(2) kg^(-2) Find the gravitational potential on the surface of the earth.