The line `x/a-y/b=1` meets the X-axis at P. Find the equation of the line perpendicular to this line at P.

The line x/a-y/b=1 cuts the x-axis at P. Find the equation of the line through p and perpendicular to the given line.

The line x/a-y/b=1 cuts the x-axis at P. The equation of the line through P and perpendicular to the given line is

Find the equation of the line perpendicular to x-axis and passing through (-2,-1).

The line (x)/(a)-(y)/(b) =1 cuts the x-axis at P. The equation of the line through P perpendicular to the given line is

the line (x)/(a)-(y)/(b)=1 cuts the x -axes at P .the equation of the line passes through point P and perpendicular to the line is:

The line 2x+3y=12 meets the x-axis at A and y-axis at B. The line through (5,5) perpendicular to AB meets the x-axis and the line AB at C and E respectively. If O is the origin of coordinates, find the area of figure OCEB.

The line 2x+3y=12 meets the x-axis at A and y-axis at B. The line through (5,5) perpendicular to AB meets the x-axis and the line AB at C and E respectively. If O is the origin of coordinates, find the area of figure OCEB.

The line x/a+y/b=1 cuts the coordinate axes at a and B a line perpendicular to AB meets the axes in P and Q. The equation of the locus of the point of intersection of the lines AQ and BP is