Light of wavelength `lambda` falls on metal having work functions `hc//lambda_(0)` . Photoelectric effect will take place only if :

Light of wavelength lamda falls on a metal having work function hc/ lamda . Photoelectric effect will take place only if

Light of wavelength falls on a metal having work function ( h_(c ))/( lambda_(0)) . Photoelectric effect will place only if

A beam of light of wavelength lambda is incident on a metal having work function phi and placed on a metal having work function phi and placed in a magnetic field B. The most energetic electrons emitted perpendicular to the field are bent in circular arcs of radius R. Then

The work function of a metal is hv_0 . Light of frequency v falls on this metal. The photoelectric effect will take place only if

The work function of a metal is hv_(0) . Light of frequency v falls on this metal. The photoelectric effect will take place only if

The work function of a metal is hv_0 . Light of frequency v falls on this metal. The photoelectric effect will take place only if

A metal has a work function phi_(0) and its corresponding threshold wavelength is lambda_(0) . If the threshold wavelength for a metal whose work function is (phi_(0))/(3) is n lambda_(0) , then what is the value of n ?

A metal has a work function phi_(0) and its corresponding threshold wavelength is lambda_(0) . If the threshold wavelength for a metal whose work function is (phi_(0))/(3) is n lambda_(0) , then what is the value of n ?