When a car moving with a speed of `36km//h` reaches an upwards inclined road of angle `30^(@)` its engine is switched off If coefficient of frition involved is `0.1` how much distance will the car move before coming to rest `Given `g = 10m//s^(2)`.

When an automobile moving with a speed of 36km//h reaches an upward inclined road of angle 30^(@) , its engine is switched off. If the coefficient of friction is 0.1, how much distance will the automobile move before coming to rest ? Take g=10ms^(-2) .

When a car moving with 36 km h^(-1) reaches an upward inclined road of angle 30^@ ,its engine is switched off.If the co-efficient of friction is 0.1,how much distance will the car move before coming to rest ?(Take = 10 m s^(-2) ).

A car is moving with a speed of 30 m/s. Find the distance covered by the car in 2s

A car is moving at a speed of 60 km//h traversing a circular road track of radius 60,m. The minumum coefficient of friction to prevent the skidding of the car is (g=10 m//s^2 )

A car is moving at a speed of 60 km//h traversing a circular road track of radius 60,m. The minumum coefficient of friction to prevent the skidding of the car is (g=10 m//s^2 )

An automobile moving at a speed of 72kmh^(-1) reaches the foot of a smooth incline, when the engine is switched off. How much distance does the automobile go up the incline before coming to rest. The angle of inclination with horizontal is 30^(@) and g=9.8 ms^(-2) ?

A jeep moving at a speed of 50 km/hr reaches the foot of smooth incline where its engine is switched off. How much distance does the jeep go up the incline before coming to rest ? The inclination of the plane to the horizontal is 45^@ and the acceleration due to gravity at the place is 9.8m/s^2

A car is moving with a speed of 30 m/s. Find the distance covered by the car in 1 minute.