The normal to curve `xy=4` at the point (1, 4) meets curve again at :

The equation of the tangent to the curve y=a+bx+cx^(2) where it meets the y-axis is 2x+y=3 if the normal to the curve at the same point meets the curve again at a point whose abscissa is,(5)/(2), then find a,b and c

If the tangent to the curve 4x^(3)=27y^(2) at the point (3,2) meets the curve again at the point (a,b) . Then |a|+|b| is equal to -

The normal to the rectangular hyperbola xy=4 at the point t_(1), meets the curve again at the point t_(2) Then the value of t_(1)^(2)t_(2) is

The normal drawn on the curve xy = 12 at point (3t, 4/t) cut the curve again at a point having parameter point t, then prove that t_1 = -16/(9t^3).

The normal to the rectangular hyperbola xy = 4 at the point t_1 meets the curve again at the point t_2 Then

If the normal to the rectangular hyperbola xy = 4 at the point (2t, (2)/(t_(1))) meets the curve again at (2t_(2), (2)/(t_(2))) , then

If the normal to the rectangular hyperbola xy = 4 at the point (2t, (2)/(t_(1))) meets the curve again at (2t_(2), (2)/(t_(2))) , then

The normal drawn on the curve xy=12 at point (3t,(4)/(t)) cut the curve again at a point having parameter point t, then prove that t_(1)=-(16)/(9t^(3))

If the normal at point 't' of the curve xy = c^(2) meets the curve again at point 't'_(1) , then prove that t^(3)* t_(1) =- 1 .