Figure given below shows the variation of potential energy function U(x), corresponding to a particle lying in a one dimensional force field. The force acting on the particle at x = 2 m is:

Given below is the plot of a potential energy function U(x) for a system, in which a particle is in one dimensional motion, while a conservative force F(x) acts on it. Suppose tha E_("mech")=8 J, the incorrect statement for this system is :

If the potential energy function of a particle is given by U=-(x^2+y^2+z^2) J, whre x,y and z are in meters. Find the force acting on the particle at point A(1m,3m,5m) .

The potential energy of a particle varies with distance x as shown in the graph. The force acting on the particle is zero at

A potential energy function for a two-dimensional force is the form U=3x^2y-7x . Find the force that acts at the point (x,y) .

A potential energy function for a two-dimensional force is the form U=3x^2y-7x . Find the force that acts at the point (x,y) .

The potential energy function of a particle in a region of space is given as U=(2xy+yz) J Here x,y and z are in metre. Find the force acting on the particle at a general point P(x,y,z).

Figure shows the displacement of a particle going along the X-axis as a function of time. The force acting on the particle is zero in the region

Figure shows the displacement of a particle going along the X-axis as a function of time. The force acting on the particle is zero in the region