` 25 x e^(-5x)`

The differential equation of y = A e^(5x) + B e^(-5x) is

int_(0)^(1) xe^(-5x) dx is equal to a) (1)/(25) - (6e^(-5))/(25) b) (1)/(25) + (6e^(-5))/(25) c) -(1)/(25) - (6e^(-5))/(25) d) (1)/(25) - (1)/(5) e^(-5)

Ingegrate the following with respect to x. (i) x^2 e^(5x) " " (ii) x^3 cos x " " (iii) x^3e^-x .

e^(5x)+e^(-5x)=

e^(5x)+e^(-5x)=

Evaluate : int (e^(5x)+e^(3x))/(e^(x)+e^(-x)) dx

Evaluate : int (e^(5x)+e^(3x))/(e^(x)+e^(-x)) dx