सरल रेखाएँ `2x+3y-4=0` तथा `6x+9y+8=0` के सापेक्ष बिंदु `(-6,2)` की स्थिति ज्ञात कीजिए ।

2x+3y=5 6x+9y=10

If 9x^2+y^2=37 and xy = 2 , x, y> 0 , then the value of (27x^3+y^3) is : यदि 9x^2+y^2=37 और xy = 2 , x, y> 0 , तो (27x^3+y^3) का मान ज्ञात कीजिए ।

If 2x + y = 6 and xy = 4, then find the value of 8x^3+y^3 is: यदि 2x + y = 6 तथा xy = 4 है, तो 8x^3+y^3 का मान ज्ञात कीजिए।

The lines x-y-6=0, 4x-3y-20=0 and 6x+5y+8=0 are:

The equation of the incircle of the triangle formed by the coordinate axes and the line 4x + 3y - 6 = 0 is (A) x^(2) + y^(2) - 6x - 6y - 9 = 0 (B) 4 (x^(2) + y^(2) - x - y) + 1 = 0 (C) 4 (x^(2) + y^(2) + x + y) + 1 = 0 (D) 4 (x^(2) + y^(2) - x - y ) - 1 = 0

The point from which the tangents to the circle x^2 + y^2 - 4x - 6y - 16 = 0, 3x^2 + 3y^2 - 18x + 9y + 6 = 0 and x^2 + y^2 - 8x - 3y + 24 = 0 are equal in length is : (A) (2/3, 4/17) (B) (51/5, 4/15) (C) (17/16, 4/15) (D) (5/4, 2/3)

The point from which the tangents to the circle x^2 + y^2 - 4x - 6y - 16 = 0, 3x^2 + 3y^2 - 18x + 9y + 6 = 0 and x^2 + y^2 - 8x - 3y + 24 = 0 are equal in length is : (A) (2/3, 4/17) (B) (17/16, 4/15) (C) (17/16, 4/15) (D) (5/4, 2/3)

The system of equations 3x + y -4=0 and 6x + 2y-8=0 has

The equation of the circle which inscribes a suqre whose two diagonally opposite vertices are (4, 2) and (2, 6) respectively is : (A) x^2 + y^2 + 4x - 6y + 10 = 0 (B) x^2 + y^2 - 6x - 8y + 20 = 0 (C) x^2 + y^2 - 6x + 8y + 25 = 0 (D) x^2 + y^2 + 6x + 8y + 15 = 0