A constant torque is acting on a wheel. If starting from rest, the wheel makes `n` rotations in `t` sec.., show that angular acceleration of the wheel is given by `alpha = 4pi n/t^(2) rad s^(2)`.

A constant torque is acting on a wheel. If starting from rest, the wheel makes n rotations in t seconds, show that the angular acceleration is given by alpha = (4pi n)/(t^(2)) rad s^(-2) .

A constant torque is acting on a wheel. If starting from rest, the wheel makes n rotations in t seconds, Show that the angular acceleration is given by alpha = \frac { 4 \pi n } { t ^ { 2 } } rad s^-2 .

A torque of 100 Nm acting on a wheel at rest, rotates it through 200 radians in 10 s. The angular acceleration of the wheel, in rad//s^(2) is

A torque of 100 Nm acting on a wheel at rest, rotatesit through 200 radiansin10 s.The angular acceleration of the wheel, in rad/s^2 is

A torque of 50 N-m acting on a wheel at rest rotates it through 200 rad in 5 sec. Its angular acceleration is -

On the application of a constant torque , a wheel is turned from rest through 400 radians in 10 s. The angular acceleration is :

On the application of a constant torque , a wheel is turned from rest through 400 radians in 10 s. The angular acceleration is :

A wheel starting from rest ia rotating with a constant angular velocity of 3 rad s^-1 . What is its angular acceleration after 4 s?

A wheel starts from rest and acquires an angular velocity of 60 rad//s in half a minute. Then its angular acceleration is