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Let f(x) = (x^2 - 1)^(n+1) (x^2 + x + 1)...

Let `f(x) = (x^2 - 1)^(n+1) (x^2 + x + 1)`. Then f(x) has local extremum at `x = 1`, when n is (A) `n = 2` (C) `n = 4` (B) `n = 3 ` (D)` n = 5 `

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