The acceleration of a particle performing S.H.M. is 12 cm/`s^(2)` at a distance of 3 cm from the mean position. Its time period is _____ .

The acceleration of a particle performing S.H.M. is 12 cm // sec^(2) cm at a distance of 3 cm form the mean position. Its period is

The acceleration of a particle performing SHM is 12cm//s^2 at a distance of 3 cm from the mean position. Calculate its time-period.

The acceleration of a particle performing SHM is 12 cm //s^(2) at a distance of 3 cm from the mean position . Calculate its time - period . Hint : a = omega^(2) x a = 12 cm//s^(2) , x=3cm Find omega T= (pi)/(omega)

The acceleration of a particle performing SHM is 12 cm //s^(2) at a distance of 3 cm from the mean position . Calculate its time - period . Hint : a = omega^(2) x a = 12 cm//s^(2) , x=3cm Find omega T= (pi)/(omega)

The acceleration of a particle performing a linear S.H.M. is 16 cm//s^(2) , when it is at a distance of 4 cm from the mean position. The period of S.H.M. is

The acceleration of a particle performing a linear S.H.M. is 16 cm//s^(2) , when it is at a dis"tan"ce of 4 cm from the mean position. The period of S.H.M. is

The acceleration of a particle performing S.H.M. at mean position is

The acceleration of a particle performing a S.H.M. is 0.12 m//s^(2) , when the particle is at a dis"tan"ce of 3 cm from its equilibrium position. What is the period of S.H.M. ?

The phase of a particle performing S.H.M. when the particle is at a distance of amplitude from mean position is

Calculate the time period of a particle whose acceleration is 5 cm s^(-2) at a distance of 5 cm from the mean posiiton.