This time period of a particle undergoing SHM is 16 s. It starts motion from the mean position. After 2 s, its velocity is 0.4 `ms^(-1)`. The amplitude is

The periodic time of a particle performing a linear S.H.M. is 12 sec. It starts from the mean position. After 2 seconds, its velocity is found to be pi cm//sec . What is the amplitude of S.H.M. ?

The time period of a particle executing S.H.M. is 1 s. If the particle starts motion from the mean position, then the time during which it will be at mid way between mean and extreme position will be

The time period of a particle executing S.H.M. is 1 s. If the particle starts motion from the mean position, then the time during which it will be at mid way between mean and extreme position will be

The time period of S.H.M. is 16 seconds and it starts motion from the equililbrium position, after two seconds the velocity is pi m//s . Then the displacement amplitude is

The time period of oscillation of a particle that executes SHM is 1.2s . The time starting from mean position at which its velocity will be half of its velocity at mean position is

The velocity of particle undergoing SHM is v at the mean position. If only amplitude is doubled, the velocity at mean position

A particular executes SHM with a time period of 16s. At time t=2s , the particle crosses the mean position while at t= 4 , its velocity is 4ms^(-1) Find its a amplitude of motion.

Time period of a particle executing SHM is 16s.At time t = 2s , it crosses the mean position . Its amplitude of motion is ( 32sqrt(2))/(pi) m . Its velocity at t = 4s is