Home
Class 11
PHYSICS
A solid sphere of uniform density and ra...

A solid sphere of uniform density and radius `R` applies a gravitational force attraction equal to `F_(1)` on a particle placed at `P`, distance `2R` from the centre `O` of the sphere. A spherical cavity of radius `R//2` is now made in the sphere as shows in figure. The particle with cavity now applies a gravitational force `F_(2)` on same particle placed at `P`. The radio `F_(2)//F_(1)` will be

Promotional Banner

Similar Questions

Explore conceptually related problems

A solid sphere of uniform density and radius R applies a gravitational force of attraction equal to F_(1) on a particle placed at P , distance 2R from the centre O of the sphere. A spherical cavity of radius R//2 is now made in the sphere as shown in figure. The particle with cavity now applies a gravitational force F_(2) on same particle placed at P . The radio F_(2)//F_(1) will be

A solid sphere of uniform density and radius R applies a gravitational force of attraction equal to F_(1) on a particle placed at P , distance 2R from the centre O of the sphere. A spherical cavity of radius R//2 is now made in the sphere as shown in figure. The particle with cavity now applies a gravitational force F_(2) on same particle placed at P . The radio F_(2)//F_(1) will be

A solid sphere of uniform density and radius R applies a gravitational force of attraction equal to F_1 on a particle placed at a distance 3R from the center of the sphere. The 1 sphere with the cavity now applies a gravitational force F_2 , on the same particle. Then ratio F_1/F_2 is

The gravitational force acting on a particle due to a solid sphere of uniform density and radius R, at a distance of 3R from the center of the sphere is F_1 . A spherical hole of radius (R/2) is now made in the sphere as shown in the figure . The sphere with hole now exert a force F_2 on the same particle , Ratio of F_1 and F_2 is

The gravitational force acting on a particle, due to a solid sphere of uniform density and radius R , at a distance of 3R from the centre of the sphere is F_1. A spherical hole of radius (R//2) is now made in the sphere as shown in diagram. The sphere with hole now exerts a force F_2 on the same particle. ratio of F_1 to F_2 is

The gravitational force acting on a particle, due to a solid sphere of uniform density and radius R , at a distance of 3R from the centre of the sphere is F_1. A spherical hole of radius (R//2) is now made in the sphere as shown in diagram. The sphere with hole now exerts a force F_2 on the same particle. ratio of F_1 to F_2 is

A solid sphere of radius R gravitationally attracts a particle placed at 3R form its centre with a force F_(1) . Now a spherical cavity of radius ((R)/(2)) is made in the sphere (as shown in figure) and the force becomes F_(2) The value of F_(1) : F_(2) is: