The two plates of a parallel plate capacitor are `4 mm` apart. A slab of dielectric constant 3 and thickness `3 mm` is introduced between the plates is so adujected that the capacitance of the capacitor becomes `(2)/(3) rd` of its original value. What is the new distance between the plates ?

The two plates of a parallel plate capacitor are 4 mm apart. A slab of dielectric constant 3 and thickness 3 mm is introduced between the plates is so adjusted that the capacitance of the capacitor becomes (2)/(3) rd of its original value. What is the new distance between the plates ?

Two plates of a parallel plate capacitor are 4 mm apart. A slab of dielectric constant 3 and thickness 3mm is introduced between the plates with the faces parallel to them. The distance between the faces is so adjusted that the capacitance of the capacitor becomes 2/3 of its original value. What is the new distance between the plates ?

A parallel plate capacitor has a capacity c. If a medium of dielectric constant K is introduced between plates, the capacity of capacitor becomes

Separation between the plates of a parallel plate capacitor is d and the area of each plates is A . When a slab of material of dielectric constant k and thickness t(t lt d) is introduced between the plates. Its capacitance becomes

Separation between the plates of a parallel plate capacitor is d and the area of each plates is A . When a slab of material of dielectric constant k and thickness t(t lt d) is introduced between the plates. Its capacitance becomes

The conducting plates of a parallel plate capacitor are separated by 2 cm from each other. A dielectric slab (k =5) of thickness 1 cm is inserted between the two plates. The distance between the plates is now so changed that the capacitance of the capacitor remains the same. What will be the new distance between the plates?

derive expression for capacitance of a parallel plate capacitor having dielectric slab of thickness .t. introduced between the plates of the capacitor.