The path difference between the two waves
`y_(1)=a_(1) sin(omega t-(2pi x)/(lambda)) and y(2)=a_(2) cos(omega t-(2pi x)/(lambda)+phi)` is

The path difference betweent the two waves y_(1)=a_(2) sin (omega t-(2pix)/(lambda)) and y_(2)= a_(2) cos (omega t-(2pi t)/(lambda)+phi) is

Path different between waves y_(1) = A_(1) sin (omega t - (2pix)/(lamda)) and y _(2) = A_(2) cos (omega t - (2pi x)/(lamda) + phi) at the point of superpositon is :

Phase difference between two waves y _(1) = A sin (omega t - kx) and y _(2)= A cos (omega t - kx) is ……

Find the phase difference betwee the two progressive wave. y_(1)=A sin ((2pi)/(T) t-(2pi)/(lambda) x) and y_(2)=A cos ((2pi)/(T) t-(2pi)/(lambda)x)

If two independent waves are y_(1)=a_(1)sin omega_(1) and y_(2)=a_(2) sin omega_(2)t then